a = 1, b = 2 then $a^b+b^{a}a^b+b^a$ =

$2^{x+3}=4^{x+1}2^\{x+3\}=4^\{x+1\}$ then x = …

$(\frac{-3}{2}{)}^{-4}\times (\frac{-3}{5}{)}^2(\backslash frac\{-3\}\{2\})^\{-4\}\backslash times(\backslash frac\{-3\}\{5\})^2$ =

$(\frac{1}{2}{)}^{-2}+(\frac{1}{3}{)}^{-2}+(\frac{1}{4}{)}^{-2}(\backslash frac\{1\}\{2\})^\{-2\}+(\backslash frac\{1\}\{3\})^\{-2\}+(\backslash frac\{1\}\{4\})^\{-2\}$ =

$(6^{-1}-8^{-1}{)}^{-1}+(2^{-1}-3^{-1}{)}^{-1}(6^\{-1\}-8^\{-1\})^\{-1\}+(2^\{-1\}-3^\{-1\})^\{-1\}$ = ……

$\frac{-1}{6}\times \frac{-1}{6}\times \frac{-1}{6}\backslash frac\{-1\}\{6\}\backslash times\backslash frac\{-1\}\{6\}\backslash times\backslash frac\{-1\}\{6\}$ = ……

$\sqrt[4]{81}-8\times \sqrt[3]{216}+15\sqrt[5]{32}+\sqrt{225}\backslash sqrt[4]\{81\}-8\backslash times\backslash sqrt[3]\{216\}+15\backslash sqrt[5]\{32\}+\backslash sqrt\{225\}$ = ……

$(12544{)}^{\frac{1}{2}}(12544)^\{\backslash frac12\}$ = ……

The multiplicative inverse of $\frac{1}{2^2}\backslash frac\{1\}\{2^2\}$ is

The multiplicative inverse of $a^{m}a^m$ is