a = 1, b = 2 then ab+baa^b+b^aab+ba =
2x+3=4x+12^{x+3}=4^{x+1}2x+3=4x+1 then x = …
(−32)−4×(−35)2(\frac{-3}{2})^{-4}\times(\frac{-3}{5})^2(2−3)−4×(5−3)2 =
(12)−2+(13)−2+(14)−2(\frac{1}{2})^{-2}+(\frac{1}{3})^{-2}+(\frac{1}{4})^{-2}(21)−2+(31)−2+(41)−2 =
(6−1−8−1)−1+(2−1−3−1)−1(6^{-1}-8^{-1})^{-1}+(2^{-1}-3^{-1})^{-1}(6−1−8−1)−1+(2−1−3−1)−1 = ……
−16×−16×−16\frac{-1}{6}\times\frac{-1}{6}\times\frac{-1}{6}6−1×6−1×6−1 = ……
814−8×2163+15325+225\sqrt[4]{81}-8\times\sqrt[3]{216}+15\sqrt[5]{32}+\sqrt{225}481−8×3216+15532+225 = ……
(12544)12(12544)^{\frac12}(12544)21 = ……
The multiplicative inverse of 122\frac{1}{2^2}221 is
The multiplicative inverse of ama^mam is
