If the length of a simple pendulum is doubled keeping its amplitude constant, its energy will be

The amplitude of oscillations of a simple pendulum of period T and length L is increased by 5%. The new period of the pendulum will be

In 20 s, two simple pendulums, P and Q, complete 9 and 7 oscillations, respectively, on the Earth. On the Moon, where the acceleration due to gravity is $\frac{1}{6}\backslash frac\{1\}\{6\}$ th that on the Earth, their periods are in the ratio

If T is the time period of a simple pendulum in an elevator at rest, its time period in a freely falling elevator will be

A seconds pendulum is suspended in an elevator moving with a constant speed in the downward direction. The periodic time (T) of that pendulum is

The total work done by a restoring force in simple harmonic motion of amplitude A and angular frequency $\omega \backslash omega$, in one oscillation is

The average displacement over a period of SHM is (A = amplitude of SHM)

Two springs of force constants $k_{1}k\_1$ and $k_{2}k\_2$ ($k_{1}k\_1$> $k_{2}k\_2$ ) are stretched by the same force. If $W_{1}W\_1$ and $W_{2}W\_2$ be the work done in stretching the springs, then

Two bar magnets of identical size have magnetic moments $M_{A}M\_A$ and $M_{B}M\_B$ . If the magnet A oscillates at twice the frequency of magnet B, then

A magnet is suspended to oscillate in the horizontal plane. It makes 20 oscillations per minute at a place where the dip angle is 30° and 15 oscillations per minute where the dip angle is 60°. The ratio of the Earth’s total magnetic field at the two places is