P = Rs 12000, R = 6%, n = 2 years then S.I. = ...........

The cost of a scooter is Rs 42,000 and the depreciation value for every year is 8% then the value of scooter after 1 year is ….

Raju took some amount from a bank at $10\frac{1}{2}\mathrm{\%}10\backslash frac\{1\}\{2\}\backslash \%$ per 1 year. He paid Rs 1863.75 as interest after $2\frac{1}{2}2\backslash frac\{1\}\{2\}$ years. Then how much amount was initially taken ?

On certain amount simple interest is $\frac{16}{25}\backslash frac\{16\}\{25\}$ th part of the amount taken then the time and rate of interest is …… (Numerically same)

On a certain amount at $12\frac{1}{2}\mathrm{\%}12\backslash frac\{1\}\{2\}\backslash \%$ rate for 1 years it becomes Rs 2437.50 then the amount is ………

On Rs 5000 at 12% per 1 year the interest for 3 years is …

On which rate Rs 500 will become Rs 605 in 3 years?

12.5% = ……

111:125 = ……

How much percentage is 16 m in 40 m ?