Let ‘O’ be the centre of circle and AB and CD’ are chords. The distance of chord AB from ‘O’ is longer than the distance of chord CD from ‘O’ then one of the following is true.

The length of a chord that passes through the centre of a circle is 14 cm then what is the radius of the circle?

Angle in a semi circle is …

Number of circles that can be drawn through three collinear points is ……

Which of the following is a FALSE statement?

In the given circle ‘O’ is the centre of the circle and AB = BC. $\mathrm{\angle }ABC+\mathrm{\angle }AOC\backslash angle\; ABC+\backslash angle\; AOC$ = 2 right angles. Then $\mathrm{\angle }AOD=\backslash angle\; AOD=$

A chord is at a distance of 8 cm from the centre of a circle of radius 17 cm. The length of the chord is

A circle is inscribed in an equilateral triangle of side 9 cm. The radius of the circle is

The radius of a circle is 13 cm and the length of one of its chords is 10 cm. The distance of the chord from the centre is

In the given figure, BOC is a diameter of a circle and AB = AC. Then, $\mathrm{\angle }ABC\backslash angle\; ABC$ =