If in the figure, $\overline{XY}\backslash overline\{XY\}$ is the perpendicular bisector to AB then AX =

In the figure, $\overrightarrow{BF}\backslash overrightarrow\{BF\}$ is the bisector of $\mathrm{\angle }ABC\backslash angle\; ABC$ then

From the figures, $\mathrm{△}ABD\cong \mathrm{△}CBD\backslash triangle\; ABD\backslash cong\backslash triangle\; CBD$ by

$\mathrm{\angle }DAC\backslash angle\; DAC$ =

Angles in same circle segment are

Angle in the semi-circle is

The process of drawing a geometrical figure by using a compass and straight edge is called

No. of circles drawn from a given point is

If in $\mathrm{△}ABC,\backslash triangle\; ABC,$ $\overrightarrow{BX}\backslash overrightarrow\{BX\}$ and $\overrightarrow{CX}\backslash overrightarrow\{CX\}$ are bisectors to the base angles then $\mathrm{\angle }BXC\backslash angle\; BXC$ =

The circumcentre ‘O’ shown in the figure is formed by the concurrence of