Potential energy of a body in the gravitational field of planet is zero. The body must be

If gravitational force of Earth disappears, what will happen to the satellite revolving round the Earth?

If $v_{e}v\_e$ and $v_{o}v\_o$ represent the escape velocity and orbital velocity of a satellite corresponding to a circular orbit of radius R respectively, then

If the kinetic energy of a satellite is $2\times 10^{4}J2\backslash times10^4\backslash ,\; J$ , then its potential energy will be

A body weighs 200 N on the surface of the Earth. How much will it weigh half way down to the centre of the Earth?

The work done to raise a mass m from the surface of the Earth to a height h, which is equal to the radius of the Earth, is:

The time period of a geostationary satellite is 24 h, at a height $6R_{E}6R\_E$ ($R_{E}R\_E$ is radius of Earth) from surface of Earth. The time period of another satellite whose height is 3.5 $R_{E}R\_E$ from surface will be

Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final – initial) of an object of mass m, when taken to a height h from the surface of Earth (of radius R), is given by,

A body mass ‘m’ is dropped from height $\frac{R}{2}\backslash frac\; R2$ , from Earth’s surface, where ‘R’ is the radius of Earth. Its speed when it will hit the Earth’s surface is ($v_{e}v\_e$ = escape velocity from Earth’s surface)

According to Kepler’s Law, the areal velocity of the radius vector drawn from the Sun to any planet always