If oxygen is present in one litre flask at pressure of $7.6\times 10^{-10}7.6\; \backslash times\; 10^\{-10\}$ mm Hg, then the number of o oxygen molecules in the flask at $0^{\circ }C0^\backslash circ\; C$ will be

4.0g of caustic soda (mol. mass 40) contains same number of sodium ions as per present in :

0.1g of a metal on reaction with dil acid gave 34.2 mL hydrogen gas at N.T.P. The equivalent weight of the metal is :

0.5g of metal on oxidation gave 0.79g of its oxide. The equivalent weight of the metal is :

74.5g of a metal chloride contains 35.5g of chlorine. The equivalent weight of the metal is:

The chloride of a metal (M) contains 65.5% of chlorine. 100 mL. of the vapour of the chloride of the metal at N.T.P. weights 0.72 g. The molecular formula of the metal chloride is:

The equivalent weight of a metal is 4.5 and the molecular weight of its chloride is 80. The atomic weight of the metal is :

The sulphate of an element contains 42.2% element. The equivalent weight would be :

 The equivalent weight of an element is 4. Its chloride has a vapour density 59.25. Then the valency of the element is :

The oxide of an element possesses the formula $M_2{O}_{3}M\_2O\_3$. If the equivalent weight of the metal is 9, then the atomic weight of the metal will be :