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Solutions Quiz-3

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10 Question

Popular Questions In Solutions Quiz-3

  • The relative lowering of vapour pressure of an aqueous solution containing non-volatile solute is 0.0125. The molality of the solution is

  • Two aqueous solutions S1S_1 and S2S_2 are separated by a semi-permeable membrane. S2S_2 has lower vapour pressure than S1S_1 of a non-volatile solute, Then

  • When 3g of a non-volatile hydrocarbon containing 94.4% carbon is dissolved in 100g benzene, the vapour pressure of benzene is lowered from 9.953 kPa to 9.823 kPa. The molecular formula of the hydrocarbon is

  • 200 mL of an aqueous solution of a protein contains 1.26 g. The osmotic pressure of this solution at 300 K is found to be 2.57×1032.57\times10^{-3}bar. Molar mass of protein will be

  • Which of the following 0.1M aqueous solution will have lowest freezing point?

  • 0.004 M Na2SO4Na_2SO_4 is isotonic with 0.01M glucose. Degree of dissociation of Na2SO4Na_2SO_4 is

  • Freezing point of a solution containing 0.1g of K3[Fe(CN)6]K_3[Fe(CN)_6](mol. wt. 329) in 100g of water (Kf=1.86 K kg mol1K_f=1.86\text{ K kg mol}^{-1}) is

  • A decimolar solution of potassium ferrocyanide is 50% dissociated at 300 K. Calculate the osmotic pressure of the solution.

  • The solutions A, B, C, and D are respectively 0.1 M glucose, 0.05 M NaCl, 0.05 M BaCl2BaCl_2 and 0.1 M AlCl3AlCl_3. which one of the following pairs is isotonic?

  • A solution containing 0.10 g of non-volatile solute X (molar mass = 100) in 200 g of benzene 0 depresses the freezing point of benzene by 0.25C0.25^\circ C while 0.50 g of another non-volatile solute 0 Y in 100 g of benzene by 0.25C0.25^\circ C. What is the molar mass of Y?