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Electrochemistry Quiz-1

Electrochemistry Quiz-1

Difficulty Level: Easy
10 Questions
4 Plays
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Popular Questions InElectrochemistry Quiz-1

1

Given that the dissociation content of acetic is 1.8×10−51.8 \times 10^{-5}1.8×10−5 and its molar conductivity at infinite dilution is 390.7 Ω−1cm−2mol−1390.7\,\Omega^{-1}{\text{cm}^{-2}\text{mol}^{-1}}390.7Ω−1cm−2mol−1 . The molar conductivity of 0.01 M acetic acid solution will be

2

The standard electrode potential (E∘E^\circE∘) for OCl−/Cl−OCl^-/Cl^-OCl−/Cl− and Cl−/12Cl2Cl^-/\frac12Cl_2Cl−/21​Cl2​ respectively are 0.94 V and - 1.36 V. The E∘E^\circE∘ value for OCl−/12Cl2OCl^-/\frac12Cl_2OCl−/21​Cl2​ will be

3

The standard electrode potentials for Zn2+/Zn,Ni2+/Ni,Zn^{2+}/Zn, Ni^{2+}/ Ni,Zn2+/Zn,Ni2+/Ni, and Fe2+/FeFe^{2+}/ FeFe2+/Fe are -0.76, -0.23, and -0.44 V respectively. The reaction X+Y2+⟶X2++YX + Y^{2+}\longrightarrow X^{2+}+YX+Y2+⟶X2++Y will be spontaneous when:

4

Ecell∘E^\circ_{cell}Ecell∘​ for the reaction, Fe+Zn2+⇌Fe2++ZnFe + Zn^{2+}\rightleftharpoons Fe^{2+}+ ZnFe+Zn2+⇌Fe2++Zn is -0.32 V. The equilibrium concentration of Fe2+Fe^{2+}Fe2+ when a piece of iron is placed in 1 M Zn2+Zn^{2+}Zn2+solution is

5

A solution contains Fe2+,Fe3+Fe^{2+},Fe^{3+}Fe2+,Fe3+ and I−I^-I− ions. This solution was treated with iodine at 35∘C35^\circ C35∘C. E∘E^\circE∘ for Fe3+/Fe2+Fe^{3+}/ Fe^{2+}Fe3+/Fe2+is + 0.77 V and for I2/2I−I_2 / 2I^-I2​/2I− is 0.536 V. The favourable redox reaction is

6

If Zn+2/ZnZn^{+2}/ZnZn+2/Zn electrode is diluted 100 times, then the change in emf is

7

The standard reduction potential values of the three metallic cation X, Y and Z are 0.52, -3.03 and -1.18 V respectively. The order of reducing power of the corresponding metals is

8

A gas Y at 1 bar is bubbled through a solution containing a mixture of 1M X and 1M Z at 25∘C25^\circ C25∘C. If the reduction potential of Z > Y > X, then

9

For the electrochemical cell, M∣M+∣∣X−∣X,EM+∣M∘=0.44 VM | M^+ || X^- | X, E^\circ_{M^+|M} = 0.44\,VM∣M+∣∣X−∣X,EM+∣M∘​=0.44V and EX∣X−∘=0.33 VE^\circ_{X|X^-}=0.33\,VEX∣X−∘​=0.33V. From this data one can deduct that

10

The value of EH2O∣H2(1bar)∣PtE_{H_2O|H_2(1bar)|Pt}EH2​O∣H2​(1bar)∣Pt​ at 298 would be

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