A particle start from rest and has a uniformly accelerated motion.s is distance travelled in time interval t = 4s to t = 5s. $s_{1}s\_1$ is distance travelled in time interval t = n and t = n+1. $\frac{S_1}{S}=\frac{15}{9}\mathrm{.}\backslash frac\{S\_1\}\{S\}=\backslash frac\{15\}\{9\}.$ n is

A ball A is thrown vertically upwards with an initial speed v. A second ball B is thrown vertically upwards from same point at same speed n second later. The two meet one another before returning back to the point of projection. The maximum value of n is

Given, $A=a\widehat{i}+b\widehat{j}A=a\backslash hat\; i+b\backslash hat\; j$ and $B=c\widehat{i}+2b\widehat{j}B=c\backslash hat\; i+2b\backslash hat\; j$. Also $a^2=c^2+n{b}^2\mathrm{.}a^2=c^2+nb^2.$ (A + B) is perpendicular to(A - B); n is

$A=10\widehat{i}-2.5\widehat{j};B=3\widehat{i}+4\widehat{j}\mathrm{.}A=10\backslash hat\; i-2.5\backslash hat\; j\backslash ,;B=3\backslash hat\; i+4\; \backslash hat\; j.$The component of A in the direction of B is

A particle moves in a horizontal circle of radius r. The angular velocity of particle varies at a constant rate $\alpha \backslash alpha$. The acceleration of the particle is

A stone of mass m, tied to one end of string , is moving in a horizontal circle. The length of string is gradually reduced in such a manner that the instantaneous tension T in string is $T=\frac{k}{r^3}T=\backslash frac\; k\{r^3\}$ where k is a constant. For the motion, the quantity that remains constant is:

A particle moving in a plane is acted upon by a force of constant magnitude. F and v denote instantaneous force and velocity of particle. F.v is zero at every moment of time. The path of particle is

The minute's hand of a clock is 30cm long. The magnitude of change in velocity of the tip of minutes hand of clock is $\frac{\pi }{6}mm{s}^{-1}\backslash frac\{\backslash pi\}\{6\}\backslash ,mms^\{-1\}$ The time interval is

In space, far off from any gravitating matter; two particles A and B move in horizontal and vertical circles of radii in ratio of 1:2. The speed of the two particles are in ratio of 3:2. Which of the following statement is correct?

if $\mathrm{\mid }A\times B\mathrm{\mid }=\sqrt{3}(A\bullet B),|A\backslash times\; B|=\backslash sqrt3(A\backslash bullet\; B),$ the value of $\frac{1}{2}\{\mathrm{\mid }A+B{\mathrm{\mid }}^2-\mathrm{\mid }A-B{\mathrm{\mid }}^2\}\backslash frac12\backslash \{|A+B|^2-|A-B|^2\backslash \}$ is: