A gas expands with temperature accending to relation $V=K{T}^{\frac{2}{3}}V=KT^\{\backslash frac23\}$, where K is any constant. The work done when the temperature changes by 60 K.

A Carnot engine absorbs $6\times 10^{5}6\backslash times10^5$ cal at $227^{\circ }C227^\backslash circ\; C$, the work done per cycle by the engine, if its sink is maintained at $127^{\circ }C127^\backslash circ\; C$ is

One gram of air initially at NTP is compressed adiabatically to half its volume, (density of air at NTP $1.29\times 10^{-3}{\text{gram/ cm}}^{3}1.29\; \backslash times\; 10^\{-3\}\; \backslash text\{gram/\; cm\}^3$, and $\gamma =1.4\backslash gamma\; =\; 1.4$) the work done in the process will be

One mole of an ideal gas of temperature $T_{1}T\_1$ expands slowly according to the law $\frac{P}{V}=\backslash frac\; PV=$ constant, its final temperature is $T_{2}T\_2$ , the work done by the gas is

An ideal gas is expanding such that $P{T}^2=PT^2=$ constant, the coefficient of volume expansion is

The freezer in a refrigerator is located on the top section so that

A diatomic gas is used in a Carnot engine as the working substance. If during the adiabatic expansion part of the cycle the volume of the gas has increased from v to 32v, the efficiency of the engine is

The amount of heat given to a system is 40 J and the amount of work done on the system is 20 J, then the change in internal energy of the system is:

A gas follows a process $T{V}^{n-1}TV^\{n\; -1\}$ = constant, the bulk modouls of the gas in the process is given by

A closed vessel 10 litre in volume contains a diatomic gas under a pressure of $10^{5}N\mathrm{/}{m}^{2}10^5\; N/m^2$. The amount of heat imparted to the gas to increase the pressure in the vessel five times will be: