In the formula $\bar{x}=a+\frac{\sum f_i{d}_i}{\sum f_i}\backslash bar\; x=\; a\; +\; \backslash frac\{\backslash sum\; f\_id\_i\}\{\backslash sum\; f\_i\}$ for finding the mean of grouped data $d_i^{\mathrm{\prime }}sd\_i\text{'}s$ are the deviations from a of

While computing mean of grouped data,we assume that the frequencies are

In the formula $\bar{x}=a+h\frac{\sum f_i{u}_i}{\sum f_i}\backslash bar\; x=\; a\; +h\; \backslash frac\{\backslash sum\; f\_iu\_i\}\{\backslash sum\; f\_i\}$, for finding the mean of grouped frequency distribution, $u_{i}u\_i$ =

The abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of a grouped data gives its

For the following distribution :

the model class is  

The times,in seconds,taken by 150 athletes to run a 110 m hurdle race is tabulated below :

The number of athletes who completed the race in less than 14.6 seconds is

Consider the following distribution :

The frequency of the class 30-40 is

Assertion (A) : If the median and mode of a frequency distribution are 150 and 154 respectively. Then its mean is 148.

Reason (R) : Mean,median and mode of a frequency distribution are related as 2 Mean = 3 Median - Mode.

Assertion (A) : The mean of terms x,y and z is y, then x + z = 3y.

Reason (R) : Mean = $\frac{sumofobservations}{Numberofobservations}\backslash frac\{sum\backslash ,of\backslash ,observations\}\{Number\backslash ,of\backslash ,observations\}$.

Assertion (A) : If the number of runs scored by 11 players of a cricket team of India are 5,19,42,11,50,30,0,52,36,27,21 then median is 30.

Reason (R) : Median = $(\frac{n+1}{2}{)}^{th}(\backslash frac\{n+1\}\{2\})^\{th\}$ value, when n is odd.

Which of the following is a measure of central tendency?

If the difference of mode and median of a data is 24, then the difference of median and mean is

If $\bar{x}\backslash bar\; x$ is the mean of $x_i^{\mathrm{\prime }}sx\_i\text{'}s$, then the value of ${\displaystyle \sum _{i=1}^n{x}_i}\backslash displaystyle\backslash sum\_\{i=1\}^\{n\}\; x\_i$ is

The mean, mode and median of grouped data will always be

The mean and median of a distribution are 14 and 15 respectively. The value of mode is