Trigonometry Quiz 9

Sin $\theta$ = $\frac{20}{29}$ then $Sin^2 \theta + cos^2 \theta$ =

If $\theta$ = 45° then the value of $\frac{1-Cos 2 \theta}{Sin 2 \theta}$ is

In $\triangle ABC$ if Sin A = $\frac{9}{15}$ then $Cosec^2A-cot^2A=$

$(1 + Tan^2 45^\circ)^2=$

$Sin^2 105^\circ+cos^2105^\circ$

Tan (B + 15°) = $\frac{1}{\sqrt3}$ then B =

Maximum value of Sin $\theta$  =

If Sec 2A = Cosec (A – 27°), then the value of $\angle A$ is

Sin (A – B) = $\frac{1}{2}$ ; Cos (A + B) = $\frac{1}{2}$ then $\angle A$ is

$Tan^2 60^\circ+2Tan^245^\circ=x\,Tan45^\circ$Then $x=$