Sin 81° + Tan 81° can be expressed as ……………

Sin (A + B) = Sin A + Sin B is true for

Ramu said Cos A = 2 ; Ravi said Cos A = 1. Do you agree with whom ?

In $\mathrm{△}ABC,\mathrm{\angle }B\backslash triangle\; ABC,\; \backslash angle\; B$ = 90° then Sin A =

In a right angled triangle the adjacent side of 30°

$Cos\theta \mathrm{.}Tan\theta =Cos\; \backslash theta\; .\; Tan\; \backslash theta\; =$

If Cos $\theta \backslash theta$ = $\frac{a}{b}\backslash frac\{a\}\{b\}$ then Cosec $\theta \backslash theta$ is equal to

Sec $\theta \backslash theta$ = $\frac{m+n}{2\sqrt{mn}}\backslash frac\{m+n\}\{2\backslash sqrt\; \{mn\}\}$ then Cosec $\theta \backslash theta$ =

$Co{s}^2\theta (1+Ta{n}^2\theta )=Cos^2\; \backslash theta\; (1\; +\; Tan^2\; \backslash theta)\; =$

$\frac{Sin\theta }{1+cos\theta }\backslash frac\{Sin\; \backslash theta\}\{1+\; cos\; \backslash theta\}$