Trigonometry Quiz 15

$\sqrt{1+Sin A}.\sqrt{1-Sin A} =$

Sin $\theta$ = $\frac{a}{b}$ ; Cos $\theta$ = $\frac{c}{d}$ then Cot $\theta$ =

Sin $\theta$ . Cot $\theta$ . Sec $\theta$ =

$\frac{\sqrt{1+Tan^2 \theta}}{\sqrt{1+Cot^2 \theta}} =$

$Sin^3 \theta \, Cos \theta + Cos^3 \theta \, Sin \theta =$

Tan $\theta$ + Cot $\theta$ = 2, then $Tan^2 \theta + Cot^2 \theta$ =

$\frac{1+Sin \theta}{\sqrt{1-Sin^2 \theta}} =$

$\frac{Sin\, \alpha}{Cos\, \alpha} . Cot\, \alpha =$

If A, B and C are interior angles of a triangle ABC, then Sin ($\frac{B + C}{2}$ ) =

$\frac{1-Tan^2 45^\circ}{1+Tan^2 45^\circ}$ can not be expressed as ………