Express Tan $\theta \backslash theta$ in terms of Sec $\theta \backslash theta$.

$\frac{Cose{c}^2\theta }{Cot\theta }-Cot\theta \backslash frac\{Cosec^2\; \backslash theta\}\{Cot\; \backslash theta\}\; -Cot\; \backslash theta$

$\sqrt{Cose{c}^2\theta -Si{n}^2\theta -Co{s}^2\theta }=\backslash sqrt\{Cosec^2\; \backslash theta\; -\; Sin^2\; \backslash theta\; -\; Cos^2\; \backslash theta\}\; =$

If cos $\theta \backslash theta$ = $\frac{2\sqrt{mn}}{m+n}\backslash frac\{2\backslash sqrt\{mn\}\}\{m\; +\; n\}$ ,then sin $\theta \backslash theta$ =

$\frac{Cosec\theta }{Cosec\theta -1}+\frac{Cosec\theta }{Cosec\theta +1}=\backslash frac\{Cosec\; \backslash theta\}\{Cosec\; \backslash theta\; -\; 1\}\; +\; \backslash frac\{Cosec\; \backslash theta\}\{Cosec\; \backslash theta\; +\; 1\}\; =$

Sec $\theta \backslash theta$ (1 – Sin $\theta \backslash theta$) (Sec $\theta \backslash theta$ + Tan $\theta \backslash theta$) =

The ratio of lengths of opposite sides of 30°, 60°, 90° is

If Sin A = Cos B, then ……………………. (A, B are acute)

$\frac{1-se{c}^{2}A}{Cose{c}^{2}A-1}=\backslash frac\{1-sec^2\; A\}\{Cosec^2\; A\; -\; 1\}\; =$

If Tan $\theta \backslash theta$ + Sec  $\theta \backslash theta$  = 8, then Sec $\theta \backslash theta$ – Tan $\theta \backslash theta$ value is