Express Tan θ\thetaθ in terms of Sec θ\thetaθ.
Cosec2θCotθ−Cotθ\frac{Cosec^2 \theta}{Cot \theta} -Cot \thetaCotθCosec2θ−Cotθ
Cosec2θ−Sin2θ−Cos2θ=\sqrt{Cosec^2 \theta - Sin^2 \theta - Cos^2 \theta} =Cosec2θ−Sin2θ−Cos2θ=
If cos θ\thetaθ = 2mnm+n\frac{2\sqrt{mn}}{m + n}m+n2mn ,then sin θ\thetaθ =
CosecθCosecθ−1+CosecθCosecθ+1=\frac{Cosec \theta}{Cosec \theta - 1} + \frac{Cosec \theta}{Cosec \theta + 1} =Cosecθ−1Cosecθ+Cosecθ+1Cosecθ=
Sec θ\thetaθ (1 – Sin θ\thetaθ) (Sec θ\thetaθ + Tan θ\thetaθ) =
The ratio of lengths of opposite sides of 30°, 60°, 90° is
If Sin A = Cos B, then ……………………. (A, B are acute)
1−sec2ACosec2A−1=\frac{1-sec^2 A}{Cosec^2 A - 1} =Cosec2A−11−sec2A=
If Tan θ\thetaθ + Sec θ\thetaθ = 8, then Sec θ\thetaθ – Tan θ\thetaθ value is